Given rhombus $ABCD$, prove:
$$AB^{2} + BC^{2} + CD^{2} + DA^{2} = AC^{2} + BD^{2}$$
So simply stated, so much said! Check out the solution HERE!
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Given rhombus $ABCD$, prove:
$$AB^{2} + BC^{2} + CD^{2} + DA^{2} = AC^{2} + BD^{2}$$
So simply stated, so much said! Check out the solution HERE!