For all real numbers, n, calculate:
$$\sqrt[3]{\dfrac{(1\cdot2\cdot4)+(2\cdot4\cdot8)+...+(n\cdot2n\cdot4n)}{(1\cdot3\cdot9)+(2\cdot6\cdot18)+...+(n\cdot3n\cdot9n)}}$$
for n=2022.
Not as bad as it looks, I promise! Check out the solution HERE.
Free study guides and discussions about various topics in Mathematics. Thanks for stopping by!
For all real numbers, n, calculate:
$$\sqrt[3]{\dfrac{(1\cdot2\cdot4)+(2\cdot4\cdot8)+...+(n\cdot2n\cdot4n)}{(1\cdot3\cdot9)+(2\cdot6\cdot18)+...+(n\cdot3n\cdot9n)}}$$
for n=2022.
Not as bad as it looks, I promise! Check out the solution HERE.